(x+1)(x^2-4x+29)=0

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Solution for (x+1)(x^2-4x+29)=0 equation: 


Simplifying
(x + 1)(x2 + -4x + 29) = 0

Reorder the terms:
(1 + x)(x2 + -4x + 29) = 0

Reorder the terms:
(1 + x)(29 + -4x + x2) = 0

Multiply (1 + x) * (29 + -4x + x2)
(1(29 + -4x + x2) + x(29 + -4x + x2)) = 0
((29 * 1 + -4x * 1 + x2 * 1) + x(29 + -4x + x2)) = 0
((29 + -4x + 1x2) + x(29 + -4x + x2)) = 0
(29 + -4x + 1x2 + (29 * x + -4x * x + x2 * x)) = 0
(29 + -4x + 1x2 + (29x + -4x2 + x3)) = 0

Reorder the terms:
(29 + -4x + 29x + 1x2 + -4x2 + x3) = 0

Combine like terms: -4x + 29x = 25x
(29 + 25x + 1x2 + -4x2 + x3) = 0

Combine like terms: 1x2 + -4x2 = -3x2
(29 + 25x + -3x2 + x3) = 0

Solving
29 + 25x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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